i believe You need to work out the middle line length using cosine rule on bottom triangle then use the sine rule to calculate the lenght you want.
Could be easier way but not sure.

i believe You need to work out the middle line length using cosine rule on bottom triangle then use the sine rule to calculate the lenght you want.
Could be easier way but not sure.

I was trying to use sohcahtoa :thinking: ..will try again

Yes sorry It's 37. I accidentally used sin 110 instead on 118. I don't think you can use soh cah toa for this as there's no right angle in either triangle.

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(18) Jump to unreadPost a commentThat's short for Opposite side.

Need an answer in Metres

Could be easier way but not sure.

Did you guys use cosine and sine rule?

QS= root (27 squared +50 squared - (2*27*50*cos82)

This gives QS= 53.4m

Now use sine rule for upper triangle:

PS= (53.4*sin38)/sin118

This gives PS=37.2m

Hope this helps.

:)

Could be easier way but not sure.

I was trying to use sohcahtoa :thinking: ..will try again

Then use the sine rule

Sin(38)/PS = Sin(118)/53.416

=> PS = 53.416 * Sin(38) / Sin(118) = 37.246m

Edit: Doh, too slow :(

thats for right angle triangles

b^2=a^2+c^2-2acCosB

Yes. How did you guess?