Anyone good with maths? Homework help needed! - HotUKDeals
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Anyone good with maths? Homework help needed!

33342 Avatar
banned6y, 11m agoPosted 6 years, 11 months ago
ok, so i'm obviously having a blonde moment not being able to do year 6 maths homework, but can anyone give me an idea of an easy how to solve this? Pic in next post

I'm sure homework wasn't this hard when I was in primary school!
33342 Avatar
banned6y, 11m agoPosted 6 years, 11 months ago
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banned#1
http://i141.photobucket.com/albums/r60/dvds2000/img001.jpg
#2
That is way hard!
#3
wow my 6yr old gets no homework, don't think he'd be able to do these!
1 Like #4
For the top one, each house has a different number between 1 and 8 amount of people in it, then u just arrange them so the 4 rows of 3 = 15?

should be the highest numbers in the corners
#5
5 in each corner house and 4 in the centre of each row - nope scrub that it says 15 in each row
#6
At that age, it is supposed to be done by trial and error.
1 Like #7
4 5 6
7 8
4 10 1
banned#8
6 1 8
2 4
7 5 3
banned#9
bethanturner
4 5 6
7 8
4 10 1


total aint 36
#10
oh forgot the total was 36 :p
#11
For the top one - as it clearly mentions there are 36 people in 8 houses - making that in each house at least 4 - so that makes it 32 people out of the total 36. The extra four go into the corner houses to make up the 15 in each row - so that each corner house 5 each.
banned#12
25
93
banned#13
sn0ttyang3l
5 in each corner house and 4 in the centre of each row - nope scrub that it says 15 in each row


each house has a different number in
cmon read question properly thats the easy bit
banned 1 Like #14
drmsa
For the top one - as it clearly mentions there are 36 people in 8 houses - making that in each house at least 4 - so that makes it 32 people out of the total 36. The extra four go into the corner houses to make up the 15 in each row - so that each corner house 5 each.


read the qustion again
slowly
banned#15
the2ocan
For the top one, each house has a different number between 1 and 8 amount of people in it, then u just arrange them so the 4 rows of 3 = 15?

should be the highest numbers in the corners


wrong do 100 lines
must try harder
#16
8 1 6
4 2
3 5 7
banned#17
thanks for all the answers so far - glad to see it wasn't just me getting stuck on it tho lol :)
rep given :)
banned#18
ktdd18
8 1 6
4 2
3 5 7


correct or have u just copied mine
#19
195
8 4
726
#20
no herewego, ktdd is just as clever as you - well i take it from your sarky replies that is what you wanted to hear
banned#21
thanks very much guys
what about the second one, is there any way of doing without guessing? (thanks to herewego1234 for getting one way of doing it!)

Does anyone else think this is hard for a year 6 (10 year old)?
#22
colinsunderland

Does anyone else think this is hard for a year 6 (10 year old)?


Yes, definitely - and it's certainly hard for this 68-year-old!

I can't fathom how to approach the first problem logically.

Nor can I see any method for answering the second problem "how many ways of making 200".

My grandson is 9, and his homework isn't this difficult.

I have much sympathy with a headteacher somewhere who has stopped homework altogether. He says the advantages of setting homework are dubious, and certainly not worth the aggravation for pupils and parents.

Anyway, what is your child's school up to, setting homework during school holidays? Kids need their rest and relaxation as much as adult workers.
#23
you need tocheck the homework properly too...
Our son brought some home and it was blatantly WRONG...
It was a reproduced sheet rather like the above from an online supply of worksheets.
I did some research and found others reporting similar problems, but the teacher had just printed it off and sent it out...

He's 10 now and Very good at maths, but his homework was not nearly challenging enough untill we complained...

He does LOVE maths, so he didn't mind ;)

Other stuff has been harder than I remember for sure...
#24
I was doing that sort of thing definitely before year 6.
#25
62
47
#26
Okay, dont worry if you or your child cant do this. Questions like these are set to see what problem solving skills children have, rather than just to see if they get the right answer.

usually they do quite a few of these with teachers, modelling how to work it out before they expect the children to be able to get to the stage of answering correctly.

You would be surprised at what children can do.
banned#27
thanks everyone for the comments
she gets quite a few like this, but usually i can see a logical way of working them out, this time either my brain went blank or it was just a case of guessing numbers
#28
3.14159265358979323846264338327950288
banned#29
sn0ttyang3l
no herewego, ktdd is just as clever as you - well i take it from your sarky replies that is what you wanted to hear


easy to give an answer after someone has already given it

and if ktdd has an iq above 167 then she may be better than me
#30
colinsunderland
thanks everyone for the comments
she gets quite a few like this, but usually i can see a logical way of working them out, this time either my brain went blank or it was just a case of guessing numbers


I couldn't see any way that you could easily work out a formula! Trial and error only for me. It gave my old grey cells a bit of a work out and I guess that's the general idea! I have no idea what I could do when I was 6 but I doubt it was stuff like this - we had weekly mental arithmetic tests!
#31
colinsunderland

what about the second one, is there any way of doing without guessing?


The only way to do it without guessing would be formulaically, and even using this you would just end up using trial and error ultimately.

Substituting each of the values for letters:

w x
y z

which leads to:

10w+x + 10w+y + 10y+z + 10x+z = 200.

====>

20w + 11x + 11y +2z = 200

or

10w +5.5(x+y) + z = 100.

with the obvious constraints of w =/ x =/ y =/ z and they are all 1-9.

From that, all that comes out obviously is that x and y are both even or both odd, but after that it's down to trial and error I'm afraid (or a mathematical calculator!)

So, yes, I think this is too hard for a 10 year old.

:thumbsup:
#32
I was doing this in my sleep when I was 6. Come on people
banned#33
stufai
The only way to do it without guessing would be formulaically, and even using this you would just end up using trial and error ultimately.

Substituting each of the values for letters:

w x
y z

which leads to:

10w+x + 10w+y + 10y+z + 10x+z = 200.

====>

20w + 11x + 11y +2z = 200

or

10w +5.5(x+y) + z = 100.

with the obvious constraints of w =/ x =/ y =/ z and they are all 1-9.

From that, all that comes out obviously is that x and y are both even or both odd, but after that it's down to trial and error I'm afraid (or a mathematical calculator!)

So, yes, I think this is too hard for a 10 year old.

:thumbsup:
banned#34
where you get that from
banned#35
stufai
The only way to do it without guessing would be formulaically, and even using this you would just end up using trial and error ultimately.

Substituting each of the values for letters:

w x
y z

which leads to:

10w+x + 10w+y + 10y+z + 10x+z = 200.

====>

20w + 11x + 11y +2z = 200

or

10w +5.5(x+y) + z = 100.

with the obvious constraints of w =/ x =/ y =/ z and they are all 1-9.

From that, all that comes out obviously is that x and y are both even or both odd, but after that it's down to trial and error I'm afraid (or a mathematical calculator!)

So, yes, I think this is too hard for a 10 year old.

:thumbsup:


big load of rubbish
#36
herewego1234
big load of rubbish


It actually makes sense
banned#37
herewego1234;7407041
easy to give an answer after someone has already given it

and if ktdd has an iq above 167 then she may be better than me

oh please zzzz zzzzz zzzz zzz

next you'll be saying you're in mensa :roll:
#38
herewego1234
and if ktdd has an iq above 167 then she may be better than me


herewego1234
big load of rubbish


Something doesn't tally up :whistling:

It's basic algebra...

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