Refer to his/her last comment, if you think 26 is the answer then you need to get some extra help and take a step back to look at what algebra is. There is no equals in your equation. You also haven't posed a question, "what is the answer?" makes no sense, I assume you mean "expand out". Treat it as a number of smaller problems, first multiply out the last two sets of brackets, then multiply the result by the first set, then either leave the 4 out or combine, up to you.

Refer to his/her last comment, if you think 26 is the answer then you need to get some extra help to to take a step back at look at what algebra is. There is no equals in your equation. You also haven't posed a question, "what is the answer?" makes no sense, I assume you mean "expand out". Treat it as a number of smaller problems, first multiply out the last two sets of brackets, then multiply the result by the first set, then either leave the 4 out of combine, up to you.

agree...
you can't get a specif value for algebra equations.
the only value you can get is for the terms X and/or Y. however this equation has two unknowns therefore impossible to get a number value... :thinking:

Refer to his/her last comment, if you think 26 is the answer then you need to get some extra help to to take a step back at look at what algebra is. There is no equals in your equation. You also haven't posed a question, "what is the answer?" makes no sense, I assume you mean "expand out". Treat it as a number of smaller problems, first multiply out the last two sets of brackets, then multiply the result by the first set, then either leave the 4 out of combine, up to you.

Refer to his/her last comment, if you think 26 is the answer then you need to get some extra help to to take a step back at look at what algebra is. There is no equals in your equation. You also haven't posed a question, "what is the answer?" makes no sense, I assume you mean "expand out". Treat it as a number of smaller problems, first multiply out the last two sets of brackets, then multiply the result by the first set, then either leave the 4 out of combine, up to you.

i havent got a clue about maths.. Im trying to help a friend by saying id ask the brainy peeps on HUKD.. thankyou all for your help :thumbsup:

It isn't always easy to get things perfectly written on a blackberry, I have edited. However, I don't think it lost its meaning, whilst the original maths question posed could require numerous workings.

It isn't always easy to get things perfectly written on a blackberry, I have edited. However, I don't think it lost its meaning, whilst the original maths question posed could require numerous workings.

I agree. :thumbsup:
I, like you, still don't know what the question is. :?

## All Comments

(30) Jump to unreadPost a commentCan you explain how you got the answer please?:thumbsup:

(4X+4Y)(32-4Y)(4Xx16)

(4X+4Y)(32-4Y)(64X)

(X+Y)(9-Y)(16X)

im LOST................???:oops:

if you are asking if I managed to get 26 out of all that then you are studying a level too high for you :p

I got 16x^2 + 4y^2 + 12xy + 32y

I dont think I have dealt with 3 brackets before tbh, and its been 11 years since i did gcse maths LOL!

I got 16x^2 + 4y^2 + 12xy + 32y

I dont think I have dealt with 3 brackets before tbh, and its been 11 years since i did gcse maths LOL!

haha.. Im hoping its right.. i have alot riding on this

That's what i got too.

is this correct then or is MrsZ correct?

4)????xSurely it would be written 4X??

Do you mean X+4??

Anyway, multiply it all up then simplify.

128X^2+128Y^2-16X^2Y-16Y^2X

or maybe this?

128X^2+128YX-16X^2Y-16XY^2

it's highly likely that the others are correct :-D

Refer to his/her last comment, if you think 26 is the answer then you need to get some extra help and take a step back to look at what algebra is. There is no equals in your equation. You also haven't posed a question, "what is the answer?" makes no sense, I assume you mean "expand out". Treat it as a number of smaller problems, first multiply out the last two sets of brackets, then multiply the result by the first set, then either leave the 4 out or combine, up to you.

http://www.google.co.uk/#hl=en&source=hp&q=4(X%2BY)(8-Y)(Xx4)&btnG=Google+Search&meta=&aq=f&aqi=&aql=&oq=&gs_rfai=&fp=8ad4ec2e82acecdc

Simples.:-D

http://www.google.co.uk/#hl=en&source=hp&q=4(X%2BY)(8-Y)(Xx4)&btnG=Google+Search&meta=&aq=f&aqi=&aql=&oq=&gs_rfai=&fp=8ad4ec2e82acecdc

Simples.:-D

I actually did clink on that link - I will send you the therapy bill.

+1

agree...

you can't get a specif value for algebra equations.

the only value you can get is for the terms X and/or Y. however this equation has two unknowns therefore impossible to get a number value... :thinking:

to to take a step back at look at what algebra is. There is no equals in your equation. You also haven't posed a question, "what is the answer?"makes no sense, I assume you mean "expand out". Treat it as a number of smaller problems, first multiply out the last two sets of brackets, then multiply the result by the first set,then either leave the 4 out of combine, up to you.This doesn't make sense to me either.

i havent got a clue about maths.. Im trying to help a friend by saying id ask the brainy peeps on HUKD.. thankyou all for your help :thumbsup:

What makes this one confusing is that you have (X x 4) rather than (X + 4) for example :thinking:

if it's for a friend, you may want to double check that they do mean (X

[COLOR="Red"]x[/COLOR]4) :thumbsup:It isn't always easy to get things perfectly written on a blackberry, I have edited. However, I don't think it lost its meaning, whilst the original maths question posed could require numerous workings.

4)????xSurely it would be written 4X??

Do you mean X+4??

Anyway, multiply it all up then simplify.

Like I said!!

:-D Well, I thought it was amusing. If you think I made a fool of myself here, cop for this! :w00t:

http://www.hotukdeals.com/item/648463/why-do-deals-disappear-2100-xbox-po

http://www.hotukdeals.com/item/648463/why-do-deals-disappear-2100-xbox-po

NO way!!

Once bitten.:w00t:

I thought that there might have been a "her" involved!

Once bitten.:w00t:

Ha ha! Who hasn't opened their gob before they put their brain in gear?

It's all good :-D

Sums = the new aphrodisiac.

haha... yes...deffo not a him,, but in this case its totally innocent.. Its a friends wife

I agree. :thumbsup:

I, like you, still don't know what the question is. :?