2 children stand 4 metres from a white line. They take turns drawing a number from a hat, the hat contains the numbers 1, 2, 3, and 4. After each child has drawn a number they return the number to the hat, and move the relevant number of metres. The game is over when either child arrives at the white line.

Put a % chance on the game finishing in exactly 3 turns.

ie. could child 1 choose 1, 1, 2 to get to the line? Also, what happens if child chooses 1 then 4? they go over the line, I presume this counts as reaching it.... Need more info.

Anyway, its friday night, If I had a pen and paper and was more awake I could sit down and figure it out, but my brain is tired tonight ( well that is my excuse anyway). My first answer is way off the mark but I am sure my second of 6.25% or less is getting closer maybe?

As Zannaz82 says there are quite a few unexplained variables. I would appreciate it if you could pm me the answer so I can go to sleep without wondering what the answer is!!

Anyway, its friday night, If I had a pen and paper and was more awake I could sit down and figure it out, but my brain is tired tonight ( well that is my excuse anyway). My first answer is way off the mark but I am sure my second of 6.25% or less is getting closer maybe?

As Zannaz82 says there are quite a few unexplained variables. I would appreciate it if you could pm me the answer so I can go to sleep without wondering what the answer is!!

Anyway, its friday night, If I had a pen and paper and was more awake I could sit down and figure it out, but my brain is tired tonight ( well that is my excuse anyway). My first answer is way off the mark but I am sure my second of 6.25% or less is getting closer maybe?

As Zannaz82 says there are quite a few unexplained variables. I would appreciate it if you could pm me the answer so I can go to sleep without wondering what the answer is!!

1, 1, 1 is the only combination and there are 60 possibilities?

so 1.66%?

or is this some riddle and its another answer? lol

EDIT: oh carp I realised im epically wrong haha! back to the drawing board. lol 1 + 1 + 1 = 3 not 4 LOL. I will leave the above there so everyone can lol at my maths ha

Anyway, its friday night, If I had a pen and paper and was more awake I could sit down and figure it out, but my brain is tired tonight ( well that is my excuse anyway). My first answer is way off the mark but I am sure my second of 6.25% or less is getting closer maybe?

As Zannaz82 says there are quite a few unexplained variables. I would appreciate it if you could pm me the answer so I can go to sleep without wondering what the answer is!!

get pen and paper :3

I wish I could stay up and work it out but I need to go to sleep. Someone will work it out for you, will check back tomorrow, if it isn't done, I will try then.

All I know is that my first answer shows how tired I am!!!! How I came up with 0% is beyond me!! I should have gone to sleep well before now! Good luck finding out the answer.

Well, if it is one child doing it in 3 turns, Asayer your original answer of 0% is correct presuming there is only 1 of each number in the hat. Since adding the lowest 3 (1+2+3=6) therefore can't happen

if there is one of each number in the hat, it can be arrived *at* in 3 turns (between the 2) by choosing either 1 or 3 first - 50% and then child 2 must choose 2 or 4 which is 66% and 50% of child 1 then choosing the correct remaining number so answer is 0.5x0.66x0.5=0.16' or roughly 17%.

Well, if it is one child doing it in 3 turns, Asayer your original answer of 0% is correct presuming there is only 1 of each number in the hat. Since adding the lowest 3 (1+2+3=6) therefore can't happen

if there is one of each number in the hat, it can be arrived *at* in 3 turns (between the 2) by choosing either 1 or 3 first - 50% and then child 2 must choose 2 or 4 which is 66% and 50% of child 1 then choosing the correct remaining number so answer is 0.5x0.66x0.5=0.16' or roughly 17%.

I could carry on with endless scenarios :P

After each child has drawn a number they return the number to the hat,

1, 1, 1 is the only combination and there are 60 possibilities?

so 1.66%?

or is this some riddle and its another answer? lol

EDIT: oh carp I realised im epically wrong haha! back to the drawing board. lol 1 + 1 + 1 = 3 not 4 LOL. I will leave the above there so everyone can lol at my maths ha

Well, if it is one child doing it in 3 turns, Asayer your original answer of 0% is correct presuming there is only 1 of each number in the hat. Since adding the lowest 3 (1+2+3=6) therefore can't happen

if there is one of each number in the hat, it can be arrived *at* in 3 turns (between the 2) by choosing either 1 or 3 first - 50% and then child 2 must choose 2 or 4 which is 66% and 50% of child 1 then choosing the correct remaining number so answer is 0.5x0.66x0.5=0.16' or roughly 17%.

I also assumed that it meant three turns total not three per child.

Okay so here comes the science/statistics:

So to get it on the third go it's going to be the first childs second go so therefore the possibilities of getting 4 exactly are:

-1+3
-3+1
-2+2

So the chance of getting any particular number is 0.25 (25%) but you also have to make sure the other person dosn't pick 4 (75% chance)

So the chance for each of all these occurring is 0.25*0.25*0.75=0.046875 (4.7%) and you have three variations of getting this therefore 0.046875*3=0.140625 (14%).

75% chance not a 4 then again 75% chance then 25% chance its the last number you need therefore 14%

I don't understand where your coming from here, they need to make the total of 4 in three moves exactly. So they cannot draw the numbers 4 or 3 at all otherwise they would be making too few a moves.

75% chance not a 4 then again 75% chance then 25% chance its the last number you need therefore 14%

I don't understand where your coming from here, they need to make the total of 4 in three moves exactly. So they cannot draw the numbers 4 or 3 at all otherwise they would be making too few a moves.

1st child has 75% chance that they pick a number that isnt 4 (game would be over in 1 move) 2nd child has 75% chance of picking a number not a 4 (2nd move) 1 child has a 25% chance of picking the last number needed to get to the line (3rd and final move)

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(63) Jump to unreadPost a commentPut a % chance on the game finishing in exactly 3 turns.

Explain your answer please,

Edited By: asayer on Apr 01, 2011 22:27Edited By: asayer on Apr 01, 2011 22:33As Zannaz82 says there are quite a few unexplained variables. I would appreciate it if you could pm me the answer so I can go to sleep without wondering what the answer is!!

As Zannaz82 says there are quite a few unexplained variables. I would appreciate it if you could pm me the answer so I can go to sleep without wondering what the answer is!!

I'm looking for answer aswel :(

As Zannaz82 says there are quite a few unexplained variables. I would appreciate it if you could pm me the answer so I can go to sleep without wondering what the answer is!!

get pen and paper :3

Edit: Just read the other comments I assumed they had to land exactly at the line to win the game.

Edited By: james132 on Apr 01, 2011 22:40so 1.66%?

or is this some riddle and its another answer? lol

EDIT: oh carp I realised im epically wrong haha! back to the drawing board. lol 1 + 1 + 1 = 3 not 4 LOL. I will leave the above there so everyone can lol at my maths ha

Edited By: numptyj on Apr 01, 2011 22:41get pen and paper :3

I wish I could stay up and work it out but I need to go to sleep. Someone will work it out for you, will check back tomorrow, if it isn't done, I will try then.

All I know is that my first answer shows how tired I am!!!! How I came up with 0% is beyond me!! I should have gone to sleep well before now! Good luck finding out the answer.

explain your answer please.....,

if there is one of each number in the hat, it can be arrived *at* in 3 turns (between the 2) by choosing either 1 or 3 first - 50% and then child 2 must choose 2 or 4 which is 66% and 50% of child 1 then choosing the correct remaining number so answer is 0.5x0.66x0.5=0.16' or roughly 17%.

I could carry on with endless scenarios :P

the combinations needed would be either 1,1,2 or 2,1,1 or 1,2,1 or 1,2,1

the odds for the first ball being picked are obviously 50% as its 2 out of the 4 balls, its is working down from there that becomes difficult.

presuming there is only 1 of each number in the hat. Since adding the lowest 3 (1+2+3=6) therefore can't happenif there is one of each number in the hat, it can be arrived *at* in 3 turns (between the 2) by choosing either 1 or 3 first - 50% and then child 2 must choose 2 or 4 which is 66% and 50% of child 1 then choosing the correct remaining number so answer is 0.5x0.66x0.5=0.16' or roughly 17%.

I could carry on with endless scenarios :P

After each child has drawn a number they return the number to the hat,

Edited By: numptyj on Apr 01, 2011 22:43so 1.66%?

or is this some riddle and its another answer? lol

EDIT: oh carp I realised im epically wrong haha! back to the drawing board. lol 1 + 1 + 1 = 3 not 4 LOL. I will leave the above there so everyone can lol at my maths ha

(_;)

if there is one of each number in the hat, it can be arrived *at* in 3 turns (between the 2) by choosing either 1 or 3 first - 50% and then child 2 must choose 2 or 4 which is 66% and 50% of child 1 then choosing the correct remaining number so answer is 0.5x0.66x0.5=0.16' or roughly 17%.

I could carry on with endless scenarios :P

Then numbers get returned to the hat though

Me now!!

But I don't, sleep it is!!! Grrrrrrrr I am not going to be able to sleep now though, things like this annoy me!

Okay so here comes the science/statistics:

So to get it on the third go it's going to be the first childs second go so therefore the possibilities of getting 4 exactly are:

-1+3

-3+1

-2+2

So the chance of getting any particular number is 0.25 (25%) but you also have to make sure the other person dosn't pick 4 (75% chance)

So the chance for each of all these occurring is 0.25*0.25*0.75=0.046875 (4.7%) and you have three variations of getting this therefore 0.046875*3=0.140625 (14%).

Possibly.... (Unintentional probability pun)

Edited By: james132 on Apr 01, 2011 22:48I bet it will be this a stupid twisted question! lol

I don't understand where your coming from here, they need to make the total of 4 in three moves exactly. So they cannot draw the numbers 4 or 3 at all otherwise they would be making too few a moves.

--

Farhad

I bet it will be this a stupid twisted question! lol

OP doesn't even know the answer lol

I bet it will be this a stupid twisted question! lol

I bet it will be this a stupid twisted question! lol

gonna be something like what i said trust me

yeah I was going over it and thinking hmm there technically arent any question marks so is there even a question haha.

I don't understand where your coming from here, they need to make the total of 4 in three moves exactly. So they cannot draw the numbers 4 or 3 at all otherwise they would be making too few a moves.