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Can anyone answer these 2 quiz questions please?? thanks 1. Add the following sum of complex numbers, (0.13 - j0.27) + (0.13 - j0.27) + (0.15 - j0.09)? 11. The answer in question 1 is g…
jakreid Avatar
7y, 6m agoPosted 7 years, 6 months ago
Can anyone answer these 2 quiz questions please??

thanks

1. Add the following sum of complex numbers, (0.13 - j0.27) + (0.13 - j0.27) + (0.15 - j0.09)?

11. The answer in question 1 is given in rectangular form. Can you give it in polar form?
jakreid Avatar
7y, 6m agoPosted 7 years, 6 months ago
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Comments/page:
#1
...um...no.... :)
#2
jasonodell;6133100
...um...no.... :)

...um ... urm ... no :w00t:
#3
i feel a headache coming on just looking at it
#4
i would try but i fear i may spontaniously combust if i do, so i wont :lol:
#5
i havent the slighest idea of where to start.... :(
#6
this part of physics?
#7
its called j notation
1 Like #8
Not done this in a while so not sure if it's correct:

1) Treat real and imaginary parts separately:

(0.13+0.13+0.15) +(-0.27+(-0.27)+(-0.09))j = 0.41 - 0.63j = z

2) To put into polar form:
Find modulus of z (i.e. square root of ((0.41)^2 + (-0.63)^2) = 0.75

Find the argument of z (drawing it into quadrants may help). As real is positive and imaginary neative, it should be in 4th quadrant.

Therefore Arg(z)= tan inverse (0.63/0.41) = 56.9 degrees

Therefore polar form = 0.75(cos(56.9) + i sin(56.9)) --- You might want to convert degrees to radians.

I denoted imaginary parts as i rather than j.
#9
thank you repped
#10
calico_cat
Not done this in a while so not sure if it's correct:

1) Treat real and imaginary parts separately:

(0.13+0.13+0.15) +(-0.27+(-0.27)+(-0.09))j = 0.41 - 0.63j = z

2) To put into polar form:
Find modulus of z (i.e. square root of ((0.41)^2 + (-0.63)^2) = 0.75

Find the argument of z (drawing it into quadrants may help). As real is positive and imaginary neative, it should be in 4th quadrant.

Therefore Arg(z)= tan inverse (0.63/0.41) = 56.9 degrees

Therefore polar form = 0.75(cos(56.9) + i sin(56.9)) --- You might want to convert degrees to radians.

I denoted imaginary parts as i rather than j.


Blimey ...simple as that !! :thinking:
#11
queenlush
Blimey ...simple as that !! :thinking:


Easy as pi (3.14159........)
:-D
#12
i swear maths stopped becoming maths past 5 years old...
#13
i got 24jj
#14
I got 38DD :-D
#15
calico_cat
Easy as pi (3.14159........)
:-D


Ooooh tres drole

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