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Can anyone answer these 2 quiz questions please?? thanks 1. Add the following sum of complex numbers, (0.13 - j0.27) + (0.13 - j0.27) + (0.15 - j0.09)? 11. The answer in question 1 is g… Read More

Can anyone answer these 2 quiz questions please??

thanks

1. Add the following sum of complex numbers, (0.13 - j0.27) + (0.13 - j0.27) + (0.15 - j0.09)?

11. The answer in question 1 is given in rectangular form. Can you give it in polar form?

thanks

1. Add the following sum of complex numbers, (0.13 - j0.27) + (0.13 - j0.27) + (0.15 - j0.09)?

11. The answer in question 1 is given in rectangular form. Can you give it in polar form?

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## All Comments

(15) Jump to unreadPost a comment...um ... urm ... no :w00t:

1) Treat real and imaginary parts separately:

(0.13+0.13+0.15) +(-0.27+(-0.27)+(-0.09))j = 0.41 - 0.63j = z

2) To put into polar form:

Find modulus of z (i.e. square root of ((0.41)^2 + (-0.63)^2) = 0.75

Find the argument of z (drawing it into quadrants may help). As real is positive and imaginary neative, it should be in 4th quadrant.

Therefore Arg(z)= tan inverse (0.63/0.41) = 56.9 degrees

Therefore polar form = 0.75(cos(56.9) + i sin(56.9)) --- You might want to convert degrees to radians.

I denoted imaginary parts as i rather than j.

1) Treat real and imaginary parts separately:

(0.13+0.13+0.15) +(-0.27+(-0.27)+(-0.09))j = 0.41 - 0.63j = z

2) To put into polar form:

Find modulus of z (i.e. square root of ((0.41)^2 + (-0.63)^2) = 0.75

Find the argument of z (drawing it into quadrants may help). As real is positive and imaginary neative, it should be in 4th quadrant.

Therefore Arg(z)= tan inverse (0.63/0.41) = 56.9 degrees

Therefore polar form = 0.75(cos(56.9) + i sin(56.9)) --- You might want to convert degrees to radians.

I denoted imaginary parts as i rather than j.

Blimey ...simple as that !! :thinking:

Easy as pi (3.14159........)

:-D

:-D

Ooooh tres drole