Do you mean would that be a 8% solution of sodium?
If so remember you need to know the concentration of what the salt is. I believe salt in sodium is 2.5x its mass in grams.

If you just want the solution of salt in water then surely that would be 13.3% not 8%?

Do you mean would that be a 8% solution of sodium?
If so remember you need to know the concentration of what the salt is. I believe salt in sodium is 2.5x its mass in grams.

If you just want the solution of salt in water then surely that would be 13.3% not 8%?

Therefore, 20grams of salt added to 150 grams of water would give a ratio of 20:150 in 170grams of solution.

This equates to 11.76% salt & 88.24% water.

:p

Yeah i forgot to add the salt, nice one. But still you often find people are actually trying to work out the sodium ratio not the salt. Thus would be a different value, so you would divide the salt by 2.5 to get the sodium concentration.

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(18) Jump to unreadPost a commentIf so remember you need to know the concentration of what the salt is. I believe salt in sodium is 2.5x its mass in grams.

If you just want the solution of salt in water then surely that would be 13.3% not 8%?

If so remember you need to know the concentration of what the salt is. I believe salt in sodium is 2.5x its mass in grams.

If you just want the solution of salt in water then surely that would be 13.3% not 8%?

this ^

Therefore, 20grams of salt added to 150 grams of water would give a ratio of 20:150 in 170grams of solution.

This equates to 11.76% salt & 88.24% water.

:p

Therefore, 20grams of salt added to 150 grams of water would give a ratio of 20:150 in 170grams of solution.

This equates to 11.76% salt & 88.24% water.

:p

Yeah i forgot to add the salt, nice one. But still you often find people are actually trying to work out the sodium ratio not the salt. Thus would be a different value, so you would divide the salt by 2.5 to get the sodium concentration.

I'm not a chemist but i was going about to find the concentration i'd find the number of moles 1st

moles= mass/molar mass

mass of salt (NaCl) = 20g from your question

molar mass = 23+ 37.5 = 60.5 gmol

so mole = 20/60.5 =0.331 mol

Concentration = moles/ volume

150ml = 0.15L

concentration = 0.331/0.15 = 2.207 mol/L

you making crystalmeth brah?

That would make a 7.4% sodium chloride solution. :thumbsup:

Therefore, 20grams of salt added to 150 grams of water would give a ratio of 20:150 in 170grams of solution.

This equates to 11.76% salt & 88.24% water.

:p

This

i guess so cos mass/volume x100 = the % solution

20/250 x 100 = 8%

lol you know better than me chesso :oops::oops:

200 = 0.8 (x+20)

= 0.8 x +16

200-16 = 0.8x

184 = 0.8x

x=230g water

20g salt in 230 g water gives a % solution of 20/250 = 8%

yeah as it will make up part of the total mass.

200 = 0.8 (x+20)

= 0.8 x +16

200-16 = 0.8x

184 = 0.8x

x=230g water

20g salt in 230 g water gives a % solution of 20/250 = 8%

i moreorless said that in my prev post :p

That's true (more or less):-D

but almost right answer, wrong reason!!:w00t: