Whats is the greatest number that can be achieved using these three numbers 1, 2, 3 I am almost certain a number greater than 6 can be achieved, I'm thinking the square root divided by one of th… Read More

7y, 2m agoPosted 7 years, 2 months ago

Whats is the greatest number that can be achieved using these three numbers

1, 2, 3

I am almost certain a number greater than 6 can be achieved, I'm thinking the square root divided by one of the numbers, but cant work it out

Thats 2 sums on one number, if you get what I mean.

You can have 1 divided by 3 to get 1/3 and then squareroot the result, you are only allowed one sum per number, else I could just keep adding 3 to 3 until I feel like I want to stop

## All Comments

(54) Jump to unreadPost a comment2/(1/(3^2)) = 18

= 8

(2+1) x 3 = 9.

No idea if anything over that though.

+1 :thumbsup:

Is that 3 divided by (1 divided by 2 sqrt)

Thanks babes x

Thats 2 sums on one number, if you get what I mean.

You can have 1 divided by 3 to get 1/3 and then squareroot the result, you are only allowed one sum per number, else I could just keep adding 3 to 3 until I feel like I want to stop

thats 10

thus a greater number then 6.

yeah but there are already results up to 18 (might not be correct though)

Yep, that's the best you can get I think

3^3

=

27+1

not 27+1 lol but 27 is the highest I believe.

Sorry couldnt see the others when i typed it.

3^3

=

27as above...

But...2 to the power of (1+3)

But...2 to the power of (1+3)

That's a mere 16 though :)

3^3

=

27what is ^ mean? :?

to the power of

throwing alternatives, the highest I agree with, i cant think of anything better.

to the power of.

yep.. and 27 is greater than 16 last time I checked too. Unless its a trick question... 27 is correct.

Yeah, such as if we were allowed to use ! (factorial :)

Does this count? :thinking:

Does this count? :thinking:

No

Does this count? :thinking:

Nope

Quite a resounding victory I think! :p

Quite a resounding victory I think! :p

Think your calculator is broke, cos mine makes that 27 :lol:

Then you forgot to use the factorial button :w00t:

(3^(2+1))! = 27! = 10888869450418352160768000000

Why not? :?

(3^(2+1))! = 27! = 10888869450418352160768000000

thats using 2 sums on one number, not permitted, sorry

cos I said so, and I make the rules.....ha ha!!

Not really, I make one sumation of 1 and 2, then the product of the result with 3, and then the factorial of the product.

No different to summing 1 and 2, and then raising the result to the power 3.