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# Any mathematicians here?

Need help working out the following question please.

See post below.

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See post below.

Rep given

Groups

Need help working out the following question please.

See post below.

Rep given

See post below.

Rep given

Original Poster

Original Poster

That's short for Opposite side.

Need an answer in Metres

Could be easier way but not sure.

Original Poster

Did you guys use cosine and sine rule?

QS= root (27 squared +50 squared - (2*27*50*cos82)

This gives QS= 53.4m

Now use sine rule for upper triangle:

PS= (53.4*sin38)/sin118

This gives PS=37.2m

Hope this helps.

Original Poster

I was trying to use sohcahtoa :thinking: ..will try again

Then use the sine rule

Sin(38)/PS = Sin(118)/53.416

=> PS = 53.416 * Sin(38) / Sin(118) = 37.246m

Edit: Doh, too slow

thats for right angle triangles

b^2=a^2+c^2-2acCosB

Original Poster

Yes. How did you guess?

Original Poster