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# Can anyone help with this Maths problem?

We've all been trying and can't work it out.

Find the values of k for which k(x to the power 2) + 8x +5 =0 has real roots.

the answer is: x is smaller than zero, x is greater than 1.

But despite various attempts and graphs drawn we cannot get from the problem to the answer

Find the values of k for which k(x to the power 2) + 8x +5 =0 has real roots.

the answer is: x is smaller than zero, x is greater than 1.

But despite various attempts and graphs drawn we cannot get from the problem to the answer

wait hold on ill get you the answer

why is the answer talking about x when we wanna know about k

To find the real roots, it comes to the formulae -b+-(sqrt)"bsquared - 4ac" etc

using only bsquared -4ac, it is possible to determine if there are real roots or no roots

bsquared-4ac = 64-20k

64-20k must be =>0 if to have real roots

so 64 - 20k => 0

solving makes 3.2 => k

or k must be equal or less than 3.2 if the equation was to have real roots

Edit: it says "real roots", so I guess one root is not good enough, so make the answer just less than 3.2

standard form is ax2 + bx + c=0

:thumbsup:

Also, don't forget that if K is variable you can have quite a few different roots for the equation.

Original Poster

However, we still think there are to many unknowns to be able to solve this?

I don't think it is asking you to solve, just what values for K would give real roots, hence not a negative sqauare root. Look again at this first quote, just consider the sqaure root part of your quadratic formula, if this is zero or greater your roots are real.

You should only be considering the discriminant