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# Friday night Questions,

Friday Night Questions.

See who is intelligent here, 2 questions for tonight,

see 1st post........,

See who is intelligent here, 2 questions for tonight,

see 1st post........,

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Friday Night Questions.

See who is intelligent here, 2 questions for tonight,

see 1st post........,

See who is intelligent here, 2 questions for tonight,

see 1st post........,

Original Poster

Put a % chance on the game finishing in exactly 3 turns.

Original Poster

Explain your answer please,

As Zannaz82 says there are quite a few unexplained variables. I would appreciate it if you could pm me the answer so I can go to sleep without wondering what the answer is!!

Original Poster

I'm looking for answer aswel

Original Poster

get pen and paper

Edit: Just read the other comments I assumed they had to land exactly at the line to win the game.

Edited by:"james132" 1st Apr 2011so 1.66%?

or is this some riddle and its another answer? lol

EDIT: oh carp I realised im epically wrong haha! back to the drawing board. lol 1 + 1 + 1 = 3 not 4 LOL. I will leave the above there so everyone can lol at my maths ha

Edited by:"numptyj" 1st Apr 2011I wish I could stay up and work it out but I need to go to sleep. Someone will work it out for you, will check back tomorrow, if it isn't done, I will try then.

All I know is that my first answer shows how tired I am!!!! How I came up with 0% is beyond me!! I should have gone to sleep well before now! Good luck finding out the answer.

Original Poster

explain your answer please.....,

if there is one of each number in the hat, it can be arrived *at* in 3 turns (between the 2) by choosing either 1 or 3 first - 50% and then child 2 must choose 2 or 4 which is 66% and 50% of child 1 then choosing the correct remaining number so answer is 0.5x0.66x0.5=0.16' or roughly 17%.

I could carry on with endless scenarios :P

the combinations needed would be either 1,1,2 or 2,1,1 or 1,2,1 or 1,2,1

the odds for the first ball being picked are obviously 50% as its 2 out of the 4 balls, its is working down from there that becomes difficult.

After each child has drawn a number they return the number to the hat,

Edited by:"numptyj" 1st Apr 2011Original Poster

(_;)

Then numbers get returned to the hat though

Me now!!

But I don't, sleep it is!!! Grrrrrrrr I am not going to be able to sleep now though, things like this annoy me!

Okay so here comes the science/statistics:

So to get it on the third go it's going to be the first childs second go so therefore the possibilities of getting 4 exactly are:

-1+3

-3+1

-2+2

So the chance of getting any particular number is 0.25 (25%) but you also have to make sure the other person dosn't pick 4 (75% chance)

So the chance for each of all these occurring is 0.25*0.25*0.75=0.046875 (4.7%) and you have three variations of getting this therefore 0.046875*3=0.140625 (14%).

Possibly.... (Unintentional probability pun)

Edited by:"james132" 1st Apr 2011I bet it will be this a stupid twisted question! lol

I don't understand where your coming from here, they need to make the total of 4 in three moves exactly. So they cannot draw the numbers 4 or 3 at all otherwise they would be making too few a moves.

--

Farhad

OP doesn't even know the answer lol

gonna be something like what i said trust me

yeah I was going over it and thinking hmm there technically arent any question marks so is there even a question haha.

1st child has 75% chance that they pick a number that isnt 4 (game would be over in 1 move) 2nd child has 75% chance of picking a number not a 4 (2nd move) 1 child has a 25% chance of picking the last number needed to get to the line (3rd and final move)