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    Horsey algebra question

    Easy one for algebra buffs

    65 Comments

    Original Poster

    http://i2.mirror.co.uk/incoming/article8780746.ece/ALTERNATES/s615b/Brainteaser-Algebra-Question.jpg

    21.

    Original Poster

    stuarthanley

    21.


    Are you sure

    archer1204

    Are you sure


    Yes

    Original Poster

    stuarthanley

    Yes


    Can i ask how you got to that answer

    22.... Oh bugger, forgot my BODMAS
    Edited by: "Robj1" 9th Oct 2016

    22

    42

    Horse is 10
    Boot is 1
    Horseshoe is 2

    BODMAS 10 X 2 + 1

    Original Poster

    Here we go can people post not just the answer but what they think the values are

    Horse is 10, the horse shoe is 2, boot is 1. so horseshoe times horse is 20 +1 is 21

    Original Poster

    stuarthanley

    Horse is 10Boot is 1Horseshoe is 2BODMAS 10 X 2 + 1


    correct but look again

    only way you xan really get mixed up is if u dont account for the two horsehoes

    48.

    Original Poster

    DarkEnergy2012

    48.


    haha any higher

    archer1204

    correct but look again


    2 boots are 2
    2 horseshoes are 4.

    There is only one of each
    Edited by: "SJHan" 9th Oct 2016

    Bodmas?.... God I hate maths (_;)

    Original Poster

    Who thinks stuart is correct or should look again

    must be 24 then...but you can only buy horse shoes in pairs

    archer1204

    haha any higher


    Original Poster

    DarkEnergy2012

    must be 24 then...but you can only buy horse shoes in pairs


    Otherwise you will end up in a lop sided horse
    http://images.fineartamerica.com/images/artworkimages/mediumlarge/1/wobbly-legged-foal-lloyd-alexander.jpg

    stuarthanley

    2 boots are 22 horseshoes are 4. There is only one of each



    I don't see how this is incorrect? Am I missing something?

    delboyd

    I don't see how this is incorrect? Am I missing something?


    It is correct. I think he was just going for more comments

    stuarthanley

    It is correct. I think he was just going for more comments



    Ah that makes more sense. Wish I'd saved myself two pieces of A5 and a lot of confusion and realised that sooner.

    21

    any brackets then multiplication & division then addition & subtraction

    so if horse=10, horseshoe=4, boot=2 its 10×4=40+2=42

    no?

    OldEnglish

    21



    I was just going to say that although I did ask elsewhere as it was frying my brain X)

    Banned

    48.....
    Edited by: "YouDontWantToKnow" 9th Oct 2016

    42
    oh darn
    2x21 then ?

    maccy1

    I was just going to say that although I did ask elsewhere as it was … I was just going to say that although I did ask elsewhere as it was frying my brain X)


    It's basic algebra maccy, thought you would have got it straight away. (_;)
    X)

    Banned

    thewongwing101

    42oh darn :(2x21 then ?



    4 x 12

    YouDontWantToKnow

    4 x 12


    nah that makes 48 can't be right

    Banned

    thewongwing101

    nah that makes 48 can't be right



    Its right

    horses 10
    horse shoes 4
    boots 2

    YouDontWantToKnow

    Its right horses 10horse shoes 4boots 2;)


    Mmmm if you get rid of the horses(and who wouldn't ?)then yes

    OldEnglish

    It's basic algebra maccy, thought you would have got it straight away. … It's basic algebra maccy, thought you would have got it straight away. (_;)X)



    Some you win...

    http://img.pandawhale.com/post-19664-Homer-simpson-brain-gif-mind-h-ypcm.gif

    ...and a lot you don't X)

    Maths wasn't my strongest subject, in fact I'd go so far as to say it was my weakest X) I used to ask the question to my maths teacher 'when would I ever need algebra and all the complicated maths fractions etc'?...he never did say, 'well, a question may come up on HUKD one day...and you may need to know the answer' X)

    Same question was posed to my Chemistry and Physics teachers as well...I was a lovely student X)

    vanquished100

    any brackets then multiplication & division then addition & subtraction … any brackets then multiplication & division then addition & subtraction so if horse=10, horseshoe=4, boot=2 its 10×4=40+2=42no?


    No

    YouDontWantToKnow

    Its right horses 10horse shoes 4boots 2;)


    No!

    The answer is 21..consider each symbol to be a variable and then we can see that we've got three linear equations with 3 variables therefore the value of each variable can be found. Suppose the horse is x, the pair of horseshoes is y and the pair of heels/boots (I'm not sure) is z..look at the first equation 3x = 30 so x= 10.. now look at the 2nd equation x + 2y = 18 now put x = 10 then you'll get y = 4.. look at the 3rd equation which is y - z = 2.. put y = 4 which will give you z = 2. Now let's look at the question which is z/2 + x(y/2) = ?? Putting the values of x,y & z we get 2/2 + 10*(4/2) = 21

    1 Horse + 1 Horse + 1 Horse = 30
    3 Horses = 30
    1 Horse = 10

    1 Horse + 2 Horseshoes + 2 Horseshoes = 18

    18 - 1 Horse = 4 Horseshoes
    18 - 10 = 4 Horseshoes
    8 = 4 Horseshoes
    2 = 1 Horseshoe

    2 Horseshoes - 2 Boots = 2
    4 - 2 Boots = 2
    4 - 2 = 2 Boots
    2 = 2 Boots
    1 = 1 Boot

    1 Boot + 1 Horse x 1 Horseshoe = ?

    Here is where observance to BODMAS will give different answers.

    a) (1 Boot + 1 Horse) x 1 Horseshoe = (1 + 10) x 2 = 22
    or
    b) 1 Boot + (1 Horse x 1 Horseshoe) = 1 + (10 x 2) = 21 <- This is my answer

    Banned

    stuarthanley

    No!



    Errr yeah
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