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# Maths problem

Whats is the greatest number that can be achieved using these three numbers

1, 2, 3

I am almost certain a number greater than 6 can be achieved, I'm thinking the square root divided by one of the numbers, but cant work it out

3+1 x 2

1+3x2=8

3/(1/(2^2)) = 12

2/(1/(3^2)) = 18

321 Lol!

kungfu;8159980

3+1 x 2

= 8

(2+1) x 3 = 9.

No idea if anything over that though.

kungfu;8159980

3+1 x 2

+1 :thumbsup:

2+1x3=9

Original Poster

r3tract;8160005

3/(sqrt(1/2)) = 12

Is that 3 divided by (1 divided by 2 sqrt)

2 divided by the square root of 1/3 =18?

3 to the power of 2 +1?

Original Poster

choc1969;8160011

2+1x3=9

Thanks babes x

Original Poster

chesso;8160023

2 divided by the square root of 1/3 =18?

Thats 2 sums on one number, if you get what I mean.

You can have 1 divided by 3 to get 1/3 and then squareroot the result, you are only allowed one sum per number, else I could just keep adding 3 to 3 until I feel like I want to stop

Original Poster

awoodhall2003;8160027

3 to the power of 2 +1?

thats 10

loll1es;8160052

thats 10

thus a greater number then 6.

3 ^ (2+1) = 27

Original Poster

awoodhall2003;8160062

thus a greater number then 6.

yeah but there are already results up to 18 (might not be correct though)

3 ^ (2+1) = 27

Yep, that's the best you can get I think

2+1 = 3
3^3
= 27

3 ^ (2+1) = 27

+1

not 27+1 lol but 27 is the highest I believe.

loll1es;8160072

yeah but there are already results up to 18 (might not be correct though)

Sorry couldnt see the others when i typed it.

3 ^ (2+1) = 27

baffledsalmon;8160085

2+1 = 33^3= 27

as above...

But...2 to the power of (1+3)

awoodhall2003;8160098

But...2 to the power of (1+3)

That's a mere 16 though

Original Poster

baffledsalmon;8160085

2+1 = 33^3= 27

what is ^ mean? :?

loll1es;8160155

what is ^ mean? :?

to the power of

That's a mere 16 though

throwing alternatives, the highest I agree with, i cant think of anything better.
loll1es;8160155

what is ^ mean? :?

to the power of.

That's a mere 16 though

yep.. and 27 is greater than 16 last time I checked too. Unless its a trick question... 27 is correct.

Original Poster

I think 27 is the highest

5nowman;8160165

yep.. and 27 is greater than 16 last time I checked too. Unless its a … yep.. and 27 is greater than 16 last time I checked too. Unless its a trick question... 27 is correct.

Yeah, such as if we were allowed to use ! (factorial

31 to the power of 2 = 961

Does this count? :thinking:

ScreechMF;8160185

31 to the power of 2 = 961Does this count? :thinking:

No

If that's allowed then 21 to the power of 3=9261

Original Poster

ScreechMF;8160185

31 to the power of 2 = 961Does this count? :thinking:

Nope

(3^(2+1))! = 10888869450418352160768000000

Quite a resounding victory I think!

Original Poster

InfernoZeus;8160225

(3^(2+1))! = 10888869450418352160768000000Quite a resounding victory I … (3^(2+1))! = 10888869450418352160768000000Quite a resounding victory I think!

Think your calculator is broke, cos mine makes that 27 :lol:

loll1es;8160241

Think your calculator is broke, cos mine makes that 27 :lol:

Then you forgot to use the factorial button :w00t:

(3^(2+1))! = 27! = 10888869450418352160768000000

! isn't permitted

! isn't permitted

Why not? :?

Original Poster

InfernoZeus;8160261

Then you forgot to use the factorial button :w00t:(3^(2+1))! = 27! = … Then you forgot to use the factorial button :w00t:(3^(2+1))! = 27! = 10888869450418352160768000000

thats using 2 sums on one number, not permitted, sorry

Original Poster

InfernoZeus;8160279

Why not? :?

cos I said so, and I make the rules.....ha ha!!

loll1es;8160306

thats using 2 sums on one number, not permitted, sorry

Not really, I make one sumation of 1 and 2, then the product of the result with 3, and then the factorial of the product.

No different to summing 1 and 2, and then raising the result to the power 3.